chuckyvittum420
chuckyvittum420 chuckyvittum420
  • 10-04-2017
  • Mathematics
contestada

Solve x3 = 64 over 27.

Respuesta :

jula1 jula1
  • 10-04-2017
x3=64
x=21,3
.....................
Answer Link
apologiabiology
apologiabiology apologiabiology
  • 10-04-2017
assuming yo meant
[tex]x^3= \frac{64}{27} [/tex]
reemmeber
[tex] \sqrt{ \frac{x}{y} } = \frac{ \sqrt{x} }{ \sqrt{y} } [/tex]

so
[tex]x^3= \frac{64}{27} [/tex]
cube root both sides
[tex]x= \sqrt[3]{ \frac{64}{27}} [/tex]
[tex]x= \frac{ \sqrt[3]{64} }{ \sqrt[3]{27} } [/tex]
[tex]x= \frac{4}{3} [/tex]
Answer Link

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