Find the dimensions of a rectangle whose width is 10 miles less than its length and whose area is 75 square miles.

L= ?
W= ?

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10-06-2018
Mathematics

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Find the dimensions of a rectangle whose width is 10 miles less than its length and whose area is 75 square miles.

L= ?
W= ?

Respuesta :

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mkryukova19 mkryukova19 · Answer 1 · 2018-06-10T09:57:39+02:00

mkryukova19 mkryukova19

10-06-2018

length = L
width =( L-10)

Area of rectangle =L*(L-10)

L*(L-10) = 75
L²-10L-75 = 0 -75= (-15)*5, -10= - 15+ 5
(L-15)(L+5)=0
L=15,L=-5

We can take only positive root,
so L=15 mi.
W=L-10=15-10=5
W=5 mi

Answer: L=15 mi, W=5mi.

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Find the dimensions of a rectangle whose width is 10 miles less than its length and whose area is 75 square miles. L= ? W= ?

Respuesta :

Otras preguntas

Find the dimensions of a rectangle whose width is 10 miles less than its length and whose area is 75 square miles.

L= ?
W= ?