Respuesta :

gmany

[tex]3^{-1}\cdot(4\cdot6)\cdot2^{-3}=\dfrac{1}{3}\cdot24\cdot\dfrac{1}{2^3}=\dfrac{24}{3\cdot8}=\dfrac{24}{24}=1\\\\Used:\\\\a^{-1}=\dfrac{1}{a}\\\\a^{-n}=\dfrac{1}{a^n}[/tex]

Answer:

here is proof that the first anwser is right <3

Step-by-step explanation:

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