deazj123 deazj123
  • 11-02-2019
  • Mathematics
contestada

Solve for x in the equation x²-12x+59=0

Respuesta :

5naka
5naka 5naka
  • 11-02-2019

[tex] {x}^{2} - 12x + 59 = 0 \\ {x}^{2} - 12x + 36 + 23 = 0 \\ {x}^{2} - 12x + 36 = - 23 \\ {(x - 6)}^{2} = - 23 \\ x - 6 = + - \sqrt{ - 23} = + - i \sqrt{23} \\ x = 6 + - i \sqrt{23} [/tex]

mean

[tex]x = 6 + i \sqrt{23} [/tex]

or

[tex] x = 6 - i \sqrt{23} [/tex]

Answer Link
mistered602 mistered602
  • 27-02-2020

Answer:

Third option

Step-by-step explanation:

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