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  • 12-06-2019
  • Mathematics
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Find the vertex of the parabola y=2x^2-16x+34

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s889114
s889114 s889114
  • 12-06-2019

Answer:

The standard equation is y=ax^2+bx+k and the vertex way is y=a(x-h)(x-h)+x

so the coordinate for x is -b/2a, for your problem a=-4   b=-16 so the coordinate for x is -(-16)/(2*(-4))=-2. Now you have to replace x=-2 in your equation y=-4(-2)^2-16(-2)-11= 5.

The vertex is (-2, 5)

Step-by-step explanation:

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