Respuesta :

sqdancefan

Answer:

  f'(x) = 8x +4h

Step-by-step explanation:

For f(x) = 4x^2 +1, we have ...

  f(x+h) = 4(x +h)^2 +1 = 4x^2 +8xh +4h^2 +1

Then ...

  f'(x) = (f(x+h) -f(x))/h = ((4x^2 +8xh +4h^2 +1) -(4x^2 +1))/h

  = (8xh +4h^2)/h

  f'(x) = 8x +4h

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