MacNCheese0816
MacNCheese0816 MacNCheese0816
  • 12-09-2019
  • Mathematics
contestada


Please help!!!! 5 TIMES I HAVE ASKED! I need real help. I can not afford to fail

Please help 5 TIMES I HAVE ASKED I need real help I can not afford to fail class=

Respuesta :

luchoprat
luchoprat luchoprat
  • 12-09-2019

Both are D

First one:

f(g(x)) =f(x^2+3) then you x^2+3 is the x you are going to introduce in the function f

f(x^2+3)= sqrroot(x^2+3-3)= sqrroot (x^2) =x

Second:

you need to leave x alone

y = 3x^2 +1

y-1 = 3x^2

(y-1)/3 = x^2

sqrroot ((y-1)/3) = x

sqrroot ((x-1)/3) = h^-1(x)

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