Answer:
Molarity of KCl = 0.03M
Explanation:
[tex]Molarity=\frac{W}{GMW} \times \frac{1000}{V(in\,ml)}[/tex]
Given
Weight of [tex]$KCl$[/tex] [tex]=6.2g[/tex]
[tex]V=0.40 L=400ml[/tex]
Gram Molecular weight[tex]=74.55g[/tex]
[tex]Therefore Molarity = \frac{6.2}{74.55}\times{1000}{400}\\ =0.03M[/tex]
