if I simplify (3b^3)^4 and in the end get 81b^12 how do I get there?

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11-10-2014
Mathematics

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if I simplify (3b^3)^4 and in the end get 81b^12 how do I get there?

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scarlettears102 scarlettears102 · Answer 1 · 2014-10-11T06:13:20+02:00

scarlettears102 scarlettears102

11-10-2014

Everything inside of the parenthesis needs to be to the 4th root. So you can see it as:

3^4 * (b^3)^4

3^4 = 3*3*3*3 = 81

And using rules of exponents, you need to multiply those exponents.

b ^ (3*4) = b^12

Put them together... 81 b^12

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