Answer:
x=0.5612
Step-by-step explanation:
-Given the functions:
[tex]y=0.115x+0.0045\ \ \ \ ...i\\\\y=0.499x-0.22\ \ \ \ \ ...ii[/tex]
We subtract equation i from ii to eliminate y and solve for x:
[tex]ii-i\\\\0=0.384x-0.2155\\\\0.384x=0.2155\\\\x=0.5612[/tex]
Hence, the value of x is 0.5612
