KL99 KL99
  • 10-09-2016
  • Mathematics
contestada

Need help solving this question B^3+1/27

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caylus
caylus caylus
  • 10-09-2016
Hello,

to solve we must have an equation.

If you mean factor then

[tex]b^3+ \dfrac{1}{3^3} =(b+ \dfrac{1}{3} )(b^2- \dfrac{b}{3} + \dfrac{1}{9}) [/tex]
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