grace2650 grace2650
  • 11-12-2020
  • Physics
contestada

Pe=___

Ke=___

Me=1920

v=_____ weight=60 kg

h=______. ke=1/2mass X velocity squared

pe=mxgxh

Respuesta :

lauraspann150 lauraspann150
  • 11-12-2020

Answer:

H = start height (v = 0)

h = present height

v = present speed

assuming no friction

total energy = PE + KE

mgH = mgh + .5mv^2

if PE = KE then

mgH = mgh + mgh

h = H/2

potential energy = kinetic energy when object is at half its start height.

Explanation:

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