Answer:
3.193 mol
Explanation:
The reaction is
[tex]N_2+3H_2\rightarrow 2NH_3[/tex]
We use the stoichiometry in order to find the moles of nitrogen required.
[tex]9.58\ \text{mol of }NH_3\times \dfrac{1\ \text{mol of }N_2}{2\ \text{mol of }NH_3}[/tex]
[tex]=3.193\ \text{mol of }N_1[/tex]
The amount of nitrogen required is 3.193 mol to produce 9.58 mol of ammonia.
