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12-01-2021
Mathematics

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sin2a + sin2b / sin2a - sin 2b = tan (a+b) / tan (a-b)

Respuesta :

surycastro142 surycastro142

12-01-2021

sin 2A + sin 2B = 2sin(A+B) cos(A-B)
sin 2A - sin 2B = 2cos(A+B)sin(A-B)

dividing both...

(2sin(A+B) cos(A-B)) / (2cos(A+B)sin(A-B))
= (sin(A+B)cos(A-B))/(cos(A+B)sin(A-B))
=tan(A+B) X cot(A-B)
=tan (A+B) / tan(A-B)

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