Answer: 4d-3
Step-by-step explanation:
A width of a pool is:
[tex]\dfrac{32d^{3}-4d^{2}-15d }{d \cdot (8d+5)}=\dfrac{d\left(32d^2-4d-15\right)}{d\left(8d+5\right)}=\dfrac{32d^2-4d-15}{8d+5}=\dfrac{\left(8d+5\right)\left(4d-3\right)}{8d+5}=\\\\=4d-3[/tex]
