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11-03-2021
Mathematics

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Which is a zero of the quadratic function f(x) = 16x2 + 32x - 9?

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11-03-2021

Step-by-step explanation:

[tex] = 16 {x}^{2} + 32x - 9 \\ = (4x + 9)(4x + 1) \\ x = - \frac{9}{4} \: or \: x = - \frac{1}{4} [/tex]

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