Answer:
123.2 Liters.
Explanation:
At STP (T = 273K & P = 1atm), one mol of any gas will occupy 22.4 liters.
With the above information in mind, we can calculate how many liters would 5.500 mol of gas occupy:
5.500 mol * 22.4 L / mol = 123.2 L
So 5.500 moles of C₃H₃ would have a volume of 123.2 liters at STP.
