Answer:
The range is [-11, ∞).
Step-by-step explanation:
f(x)=3x^2+6x-8
This is a parabola which opens upwards.
Convert to vertex form:
= 3(x^2 + 2x) - 8
= 3 [ (x + 1)^2 - 1] - 8
= 3(x + 1)^2 - 3 - 8
= 3(x + 1)^2 - 11.
The minimum value is -11 so the range is [-11, ∞).
Step-by-step explanation:
