Answer:
when x=0 ,y=7
when x=-1, y=6
Step-by-step explanation:
Taking [tex]y=x^{2} +2x+7, y=x+7[/tex] as equation 1 and 2 respectively
Inserting equation 2 in 1,
[tex]x+7=x^{2} +2x+7\\[/tex]
getting rid of 7 since its in both the sides with the same + signs,
[tex]x^{2} +2x-x=0\\x^{2} +x=0\\x(x+1)=0\\x=0 / x=-1[/tex]
when x=0 ,
y=7
when x=-1 , y=6
