Answer:
The genotype of both parents will be heterozygous for the trait, Ii.
Explanation:
Let us assume that the shape of the seeds is controlled by a single diallelic gene.
The individual with constricted seeds must have two recessive alleles i in its genotype ⇒ ii.
One of the i alleles was inherited from one of the parental plants, while the other parental plant provided the other i allele. So both parental plants must carry the recessive allele in their genotype.
We know that both parental plants have inflated seeds, which is the dominant phenotype.
So, if both parental plants have inflated seeds and also carry the recessive allele, then the parentals´ genotype must be heterozygous, Ii.
Both plants exhibit the dominant inflated phenotype but carry a recessive allele which will be provided to some of the descendants. These last individuals will have constricted seeds.