9514 1404 393
Answer:
an = 243·(1/3)^(n-1) = 3^(6-n)
Step-by-step explanation:
This geometric sequence has a first term of a1=243 and a common ratio of r = 81/243 = 1/3. The general term for it is ...
an = a1·r^(n-1)
an = 243·(1/3)^(n-1)
Making use of the rules of exponents, this can be simplified to ...
an = 3^5·(3^-1)^(n-1) = 3^(5-n+1)
an = 3^(6-n)
