Answer:
Yes lolololololololololololololololol
Hello,
Step-by-step explanation:
[tex]\dfrac{1}{2}*10^{8t}=73 \\\\10^{8t}=146 \\\\8t=log_{10}(146)\\\\t=\dfrac{log_{10}(146)}{8} \\\\\\t=0,27054410...\approx{0.27}[/tex]
