jodidaniel5 jodidaniel5
  • 11-12-2021
  • Mathematics
contestada



Find the equation of the line l that is perpendicular to -3x + 6y = 11 and I passes
through the point (-2, 3)

Respuesta :

Аноним Аноним
  • 11-12-2021

Answer:

Step-by-step explanation:

-3x + 6y = 11

Put into slope-intercept form to find the slope

6y = 3x + 11

 y = 3x/6 + 11/6

 y = ½x + 11/6

so slope is ½

perpendicular lines have negative reciprocal slopes, so our perpendicular line has slope -2

the slope point form of the perpendicular line will be

(y - 3) = -2(x -(-2))

(y - 3) = -2(x +2)

the slope intercept form will be

y = -2x - 4 + 3

y = -2x - 1

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