Step-by-step explanation:
[tex]let \: angle \: be \: \alpha \\ \tan( \alpha ) = \frac{p}{b} \\ \tan(69.9) = \frac{9.7}{bc} \\ bc = \frac{9.7}{2.73} \\ bc = 3.55 \\ by \: using \: pythagorean \: theorem \\ ab = \sqrt{ {9.7}^{2} } + {2.73}^{2} \\ ab = 10.07[/tex]
