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10-08-2017
Mathematics

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What is the center and radius of the circle with equation x2 + y2 + 6x + 16y + 64 = 0?

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10-08-2017

Hello,

By making factors:
[tex]x^2+y^+2+6x+16y+64=0\\ x^2+6x+9+y^2+16y+64-9=0\\ (x+3)^2+(y+8)^2=9\\ radius=3 [/tex]

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